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Fix NameError in sweep error handler lambda

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Python 3.13 deletes exception variables after the except block.
Capture the error string before passing to the lambda.

Co-Authored-By: Claude Opus 4.6 <noreply@anthropic.com>
This commit is contained in:
Alexander Grabowski
2026-03-11 16:02:16 +07:00
parent aced4f1e23
commit 3f46029204
1 changed files with 2 additions and 1 deletions
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3
testbench/gui.py
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@@ -1159,8 +1159,9 @@ class TestbenchGUI(tk.Tk):
self._console(msg, "warn") self._console(msg, "warn")
self.after(0, lambda: self._svi_status.config(text=msg)) self.after(0, lambda: self._svi_status.config(text=msg))
except Exception as e: except Exception as e:
err_msg = f"Error: {e}"
self._console(f"Sweep error: {e}", "error") self._console(f"Sweep error: {e}", "error")
self.after(0, lambda: self._svi_status.config(text=f"Error: {e}")) self.after(0, lambda: self._svi_status.config(text=err_msg))
finally: finally:
self.after(0, self._sweep_vi_done) self.after(0, self._sweep_vi_done)